Imaginary numbers | Solutions with procedure

Here are the solutions to the exercises I gave you here!

Notice that cosine is an even function, therefore cos(-pi)=cos(pi).

The logarithm in base 3 of 3 is 1 because 1 is the number you must raise 3 to in order to get 3.

Now, why is theta raised to the log in base theta of negative i equal to negative i, i.e. the argument of the logarithm? That’s a property:

Another property is the following:

Hope this was useful! If you have any doubt leave a comment and I will be happy to help!

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